Many newspapers carry a certain puzzle in which the reader must unscramble lette
ID: 3182633 • Letter: M
Question
Many newspapers carry a certain puzzle in which the reader must unscramble letters to form words. How many ways can the letters of
LAGONL
be arranged? Identify the correct unscrambling, then determine the probability of getting that result by randomly selecting one arrangement of the given letters.
What is the correct unscrambling of lagonl ?
What is the probability of coming up with the correct unscrambling through random letter selection?
If you know the names of the remaining
tenten
2. students in the spelling bee, what is the probability of randomly selecting an order and getting the order that is used in the spelling bee?
P(selecting the correct spelling bee
order)=
4. Assume the readings on thermometers are normally distributed with a mean of 0degrees°C and a standard deviation of 1.00degrees°C.Find the probability that a randomly selected thermometer reads between negative 2.042.04 and negative 1.491.49 and draw a sketch of the region ? The probability is
5. Assume that the readings on the thermometers are normally distributed with a mean of 0 degrees0° and standard deviation of 1.00degrees°C. Assume 3.23.2% of the thermometers are rejected because they have readings that are too high and another 3.23.2% are rejected because they have readings that are too low. Draw a sketch and find the two readings that are cutoff values separating the rejected thermometers from the others. The cutoff values are___ degrees.
Explanation / Answer
. Assume the readings on thermometers are normally distributed with a mean of 0degrees°C and a standard deviation of 1.00degrees°C.Find the probability that a randomly selected thermometer reads between negative 2.042.04 and negative 1.491.49 and draw a sketch of the region ? The probability is
Ans:Z(-2.04)=-2.04-0/1
=-2.04
Z(-1.49)=-1.49-0/1
=-1.49
P(-2.04<x<-1.49)=NORMSDIST(-1.49)-NORMSDIST(-2.04)
=-0.4744
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