A candy company claims that 18% of its plain candies are orange, and a sample of
ID: 3182534 • Letter: A
Question
A candy company claims that 18% of its plain candies are orange, and a sample of 200 such candies is randomly selected. Find the mean and standard deviation for the number of orange candies in such groups of 200. mu = 36 sigma = 5.4 (Round to one decimal place as needed.) A random sample of 200 candies contains 19 orange candies. Is this result unusual? Does it seem that the claimed rate of 18% is wrong? Yes, because 19 is greater than the maximum usual value. Thus, the claimed rate of 18% is not necessarily wrong. Yes, because 19 is within the range of usual values. Thus, the claimed rate of 18% is probably wrong. Yes, because 19 is below the minimum usual value. Thus, the claimed rate of 18% is probably wrong. No, because 19 is within the range of usual values. Thus, the claimed rate of 18% is not necessarily wrong.Explanation / Answer
as mean =np =200*0.18=36
and std deviation =(np(!-p))1/2 =5.4
b)P(X<=19) =P(Z<(19.5-36)/5.4_)=P(Z<-3.0369)=0.0012
hence option C is correct
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.