A nutritionist wants to determine how much time nationally people spend eating a

Question

A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random of 1002 people age 15 or older, the mean amount of time spent eating or drinking per day is 7.79 hours with a standard deviation of 0 59 hour. Complete parts through below. distribution of the sample mean will be approximately normal. Since the distribution of time spent eating and drinking each day is normally distributed, the sample most be large so that the distribution of the sample mean will be approximately normal. the distribution of the sample mean will never be approximately normal. in 2010. there were over 200 million people nationally age 15 or older. Explain why this along with the fact that the data were obtained using a random sample satisfies the requirements for constructing a confidence interval. the sample size is greater than 5% of the population. the sample size is greater than 10% of the population the sample size is less than 5% of the population the sample size is less than 10% of the population. Determine and interpret a 95% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day. Select the correct choice below and fill in the answer boxes if applicable in your choice (Typo integers or decimals rounded to three decimal places as needed Use ascending order.) the nutritionist is 95% confident that the amount of time spent eating or drinking per day for any individual Is between and hours the nutritionist is 95% confident that the mean amount of time spent eating or drinking per day Is between and hours. There is a 95% probability that the mean amount of time spent eating or drinking per day is between and hours. the requirements for constructing a confidence interval ate not satisfied.

Explanation / Answer

c) z value at 95% confidence interval = 1.96

mean = 1.79 , std. deviation = 0.59, n = 1002

CI = mean +/- z * (s / sqrt(n))

= 1.79 + /- 1.96 * ( 0.59/sqrt(1002))

= (1.753 , 1.826)

Answer is option B)

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