take a Test daniela martinez https/www.mathxl.com/Student/Player Test testld 156

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take a Test daniela martinez https/www.mathxl.com/Student/Player Test testld 1562881248 centenwin yes Stat One Sp17 TR 6:30 am. LBCC daniela martinez 3/25/17 2:32 PM Test: Exam One (Ch1-Ch4)Sp17 Time Remaining: 003421 Submit Test This Question: 3 pts 2 of 26 (15 This Test: 58 pts possible Heights of women have a bel-shaped distribution with a mean of 165 om and a standarddeviation of 7 am Using Chebyshev's theorem, what do we know about the peroentage of women with heights that are within 2 ofthe mean? What are the minimum and maximum heights that are within 2 standard devations ofthe mean? least of women have heights within 2 standard deviations of 165 cm. (Round to the nearest percent as needed) The minimum height that is within 2 standard deviations of the mean is am The maximum height that is within 2 standard deviatons of the mean is am. Enter your answer in each of the answer boxes. O Ask me anything

Explanation / Answer

from above % women with in 2 standard deviation =(1-1/k2)*100 =(1-1/4)*100 =75%

minimum height within 2 standard deviation =165-2*7=151

maximum height within 2 standard deviation =165+2*7=179

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