Assume that a procedure yields a binomial distribution with n trials and the pro

Question

Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the given values of n and p to find the mean and standard deviation

sigma .

Also, use the range rule of thumb to find the minimum usual value

mu minus 2 sigma2

and the maximum usual value

mu plus 2 sigma+2.

n equals=1588

p equals=1 1/2

muequals=?

sigmaequals=?

(Round to one decimal place as needed.)

mu minus 2 sigma2equals=?

(Round to one decimal place as needed.)

mu plus 2 sigma+2equals=?

(Round to one decimal place as needed.)

Explanation / Answer

n = 1588, p = 1/2, q = 1 - p = 1/2

(a) = np = 1588 * 1/2 = 794

(b) = (npq) = (1588 * 1/2 * 1/2) = 19.9

(c) - 2 = 794 - 2 * 19.92 = 754.2

(d) + 2 = 794 + 2 * 19.92 = 833.8

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