In a 1994 study, 164 pregnant, HIV-positive women were randomly assigned to rece

Question

In a 1994 study, 164 pregnant, HIV-positive women were randomly assigned to receive the drug AZT during pregnancy and 160 such women were randomly assigned to a control group that received a placebo. It turned out that 40 of the mothers in the control group gave birth to babies who were HIV-positive, compared to only 13 in the AZT group.

How should these data be displayed or summarized? Select all that apply.

Question 9 options:

1.Boxplot

2.Histogram

3.Segmented bar graph

4.Two-way table

B. What is the difference in proportion of woman having HIV positive babies between the two groups? Round to two decimal places and use AZT - Placebo as the order of subtraction.

C .Calculate the relative risk of a baby being born HIV- positive, comparing those in the placebo group to those in the AZT group. Round your answer to two decimal places.

1.Boxplot

2.Histogram

3.Segmented bar graph

4.Two-way table

B. What is the difference in proportion of woman having HIV positive babies between the two groups? Round to two decimal places and use AZT - Placebo as the order of subtraction.

C .Calculate the relative risk of a baby being born HIV- positive, comparing those in the placebo group to those in the AZT group. Round your answer to two decimal places.

Explanation / Answer

A) The data can be displayed as Segmented Bar Graph Two way table B) Proportion of women having HIV positive babies 1) Treated with AZT = 13/164 = 0.079 2) Placebo group = 40/160 = 0.25 Difference in proportion = 0.079 - 0.4 = -0.171 Difference in proportion of woman having HIV positive babies between the two groups = - 0.171 C) Proportion of women having HIV positive babies 1) Treated with AZT = 13/164 = 0.079 2) Placebo group = 40/160 = 0.25 Relative Risk = 0.25/0.079 = 3.17 Hence Relative risk of a baby being born HIV- positive, comparing those in the placebo group to those in the AZT group = 3.17

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