A study was conducted to determine the effectiveness of two teaching methods. St

Question

A study was conducted to determine the effectiveness of two teaching methods. Students were randomly divided into two groups; group 1 was taught by method 1 and group 2 was taught by method 2. An exam was given to all of the students and the scores were reported. The results are summarized below: If needed, |d| = 6.5, s_d = 3.6, and Satterthwaite's approximate degrees of freedom are 90.41. a. Find, but do not interpret, a 95% Cl for the difference in average test grades. b. Using the confidence interval, is there evidence to suggest that one method is superior to the other? If so, which one is better and why? If not, why not?

Explanation / Answer

from above std error of differnece =3.6

and for 90degree of freedoma nd 95% CI,t =1.9867

hence confidence interval =dbar +/- t*std error =-0.6520 ; 13.6520

b) we cannot suggest that one method is superior over other as our confidence interval contains 0 which means differnce b/w them is varying on both sides/..

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