*Exercise 5: Assume weights of football players are approximately normally distr
ID: 3179919 • Letter: #
Question
*Exercise 5: Assume weights of football players are approximately normally distributed, and assume is known from a prior study to be 35 lbs. Fifteen ARC football players were randomly sampled and weighed and their weights are given below. Find a 90% confidence interval estimate of the average weight of ARC football players. Round to the nearest tenths place. 175 180 180 185 190 190 195 212 215 220 225 240 250 270 295
Q: construct a 90% confidence interval estimate of the average weight of ARC football players using the sample data above (in exercise 5) but assume is unknown so use your Sample standard deviation calculated from the data. Round to the nearest tenths place.
Explanation / Answer
1)
from above std error of mean =std deviation/(n)1/2 =8.75
for 90% CI, z=1.6449
hence confidence interval =sample mean +/- z*Std error =200.4 ; 229.2
2) for
for 90% CI and 15 degree if freedom t =1.7531
hence confidence interval =sample mean -/+ t*std error =198.6 ; 231.0
X 175.000 180.000 180.000 185.000 190.000 190.000 195.000 212.000 215.000 220.000 225.000 240.000 250.000 270.000 295.000 mean(X) 214.800Related Questions
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