At a factory that produces pistons for cars, Machine 1 produced 594 satisfactory
ID: 3178578 • Letter: A
Question
At a factory that produces pistons for cars, Machine 1 produced 594 satisfactory pistons and 396 unsatisfactory pistons today. Machine 2 produced 720 satisfactory pistons and 180 unsatisfactory pistons today. Suppose that one piston from Machine 1 and one piston from Machine 2 are chosen at random from today's batch. What is the probability that the piston chosen from Machine 1 is satisfactory and the piston chosen from Machine 2 is unsatisfactory? Do not round your answer. (If necessary, consult a list of formulas.)Explanation / Answer
For Machine 1,
P(Satisfactory Piston) = 594 / (594 + 396) = 0.6
For Machine 2,
P(Unsatisfactory Piston) = 180 / (180 + 720) = 0.2
Hence,
P(Satisfactory piston from Machine 1 and Unsatisfactory piston from Machine 2)
= (0.6)(0.2)
= 0.12
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