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At a factory that produces pistons for cars, Machine 1 produced 594 satisfactory

ID: 3178578 • Letter: A

Question

At a factory that produces pistons for cars, Machine 1 produced 594 satisfactory pistons and 396 unsatisfactory pistons today. Machine 2 produced 720 satisfactory pistons and 180 unsatisfactory pistons today. Suppose that one piston from Machine 1 and one piston from Machine 2 are chosen at random from today's batch. What is the probability that the piston chosen from Machine 1 is satisfactory and the piston chosen from Machine 2 is unsatisfactory? Do not round your answer. (If necessary, consult a list of formulas.)

Explanation / Answer

For Machine 1,

P(Satisfactory Piston) = 594 / (594 + 396) = 0.6

For Machine 2,

P(Unsatisfactory Piston) = 180 / (180 + 720) = 0.2

Hence,

P(Satisfactory piston from Machine 1 and Unsatisfactory piston from Machine 2)

= (0.6)(0.2)

= 0.12

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