The distribution of the number of Halloween treats consumed on Halloween night h

Question

The distribution of the number of Halloween treats consumed on Halloween night has a mean of 10 and a standard deviation of 6.
What percentage of children ate 15 or more treats? The distribution of the number of Halloween treats consumed on Halloween night has a mean of 10 and a standard deviation of 6.
What percentage of children ate 15 or more treats? The distribution of the number of Halloween treats consumed on Halloween night has a mean of 10 and a standard deviation of 6.
What percentage of children ate 15 or more treats?

Explanation / Answer

here from normal distribution : zscore =(X-mean)/std deviation

hence P(X>15)=1-P(Z<(15-10)/5)=1-P(Z<1)=1-0.8413=0.1587 hence 15.87%

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.