According to data, a particular brand of cigarettes contain an average of 1.6 mi
ID: 3177553 • Letter: A
Question
According to data, a particular brand of cigarettes contain an average of 1.6 milligrams of nicotine. An advocacy group commissions an independent test to see if the mean nicotine content is higher than the industry laboratory claims.
(a) What are H0 and Ha?
H0: < 0.0 mg; Ha: = 0.0 mg
H0: = 1.6 mg; Ha: 1.6 mg
H0: = 1.6 mg; Ha: > 1.6 mg
H0: = 0.0 mg; Ha: > 0.0 mg
H0: > 1.6 mg; Ha: = 1.6 mg
(b) Suppose that the test statistic is z = 2.35. Is this result significant at the 5% level?
Yes, because z > 1.645 and P < 0.05.
Yes, because z < 1.645 and P < 0.05.
No, because z > 1.645 and P > 0.05.
No, because z < 1.645 and P > 0.05.
Yes, because z > 1.645 and P > 0.05.
(c) Is the result significant at the 1% level?
No, because z > 2.326 and P > 0.01.
Yes, because z < 2.326 and P < 0.01.
Yes, because z > 2.326 and P < 0.01
No, because z < 2.326 and P > 0.01.
No, because z > 2.326 and P > 0.01.
Explanation / Answer
null, Ho: =1.6
alternate,mean nicotine content is higher than the industry laboratory claims H1: >1.6
RIGHT TAILED
Critical Value
The Value of Z at LOS is +1.645
Yes, because z > 1.645 and P < 0.05.
P-Value : Right Tail - Ha :( P > 2.35) = 0.0094
Yes, because z > 2.326 and P < 0.01
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