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Question

D New tab ucA D Developmental Theo My Tubote. Lebron Online Finis lest belore diding Save and submit Remaining Time: 1 hour, 54 minutes, 23 seconds. QUESTION 1 1 points save Assw You work at a company that processes ear insurance b been to support applications The company insures vehicles the insuramce sales manager by providing some statistics. Given the following information, draw ajeint probability table. moderate, high) oher risk factors include maritalstatus (married, unmarriedy. you have pendent. 1. What the probablity of being unmarried Put answer in probabiiies not percents You answer must be between 0 and Lead with a o prior to the decima point) QUESTION 2 points Save Answer 2What the probabilty of being a customer rated MoDERATE esk who is UNMARRIED? Put answer in Pobabities, o percents. Lead win pior to decima point and use4decima politsu QUESTION 3 1 points save Answer Take this joint probability table and daw a Probabaty 3 Looking at the first branch and the top branch of that branch, what is POB1IA1 equal to? a

Explanation / Answer

Answer to the question below:

P( high risk) = .20
P( low risk) = .45
P( mid risk) = 1-.45-.20 = .35
P( married) = .65
P( unmarried) = 1-P(married) = 1-.65=.35

1. P( beng unmarried) = .35 ( calculated above)

2. P( moderate who is unmarried) = P(mid risk)*P(unmarried) = .35*35 = .1225

3.

A1 will the 1st variable ( risk types) 1st mention i.e. Low Risk

B1 is the 1st mention of 2nd variable type ( marrined/unmarried) : Married

Hence, we solve the problem considering above things:

P(B1|A1) = Probability , given he /she is low risk to be married)

= .45*.65/ .45

=.65

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