Given the following information obtained four normally distributed populations,

Question

Given the following information obtained four normally distributed populations, construct an ANOVA table. Use Table 4. (Do not round intermediate calculations. Round answers except "dt" to 2 decimal places) SST = 70.47; SSTR = 11.34; c = 4; n_1 = n_2 = n_3 = n_4 = 8 At the 5% significance level, what is the conclusion to the ANOVA test of mean differences? Reject H_0; we can conclude that some means differ. Reject H_0; we cannot conclude that some means differ Do not reject H_0; we can conclude that some means differ Do not reject we conclude that one means differ.

Explanation / Answer

Since F is less than F critical, we fail to reject the null hypothesis. So option 4 is correct.

Source SS df MS F F Critical Betwwen Groups 11.34 3 3.78 M S Between/ MS Within =1.790 2.947 Within Groups 59.13 31-3 = 28 SS within/df = 2.111786 Total 70.47 4*8 -1 =31

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