Suppose X is normally distributed with mean mu = 11.2 and standard deviation sig

Question

Suppose X is normally distributed with mean mu = 11.2 and standard deviation sigma = 2.1. Which Excel function should be used to find P(X greaterthanorequalto 9)? NORM.S.INV(9) =NORM.DIST(9, 11, 2, 2, 1, TRUE) =NORM.INV(9, 11, 2.1) =NORM.S.DIST(9, TRUE) Suppose X is normally distributed with mean 11 and standard deviation 1. Which of the following gives the probability that 9.5 lessthanorequalto X lessthanorequalto 12.2? =1- (NORM.DIST(12, 2, 11, 1, TRUE) = NORM.DIST(9.5, 11, 1, TRUE)) =(NORM.DIST(12, 2, 11, 1. TRUE) NORM.DIST(9, 5, 11, 1, TRUE)) -1, =NORM.DIST(12.2, 11, 1, TRUE) = NORM.DIST(9, 5, 11, 1. TRUE) =NORM.DIST(9.5, 11, 1, TRUE) =NORM.DIST(12, 2, 11, 1, TRUE)

Explanation / Answer

Question 3 is correctly marked

Question 4 should be option C because we need to subtract the two probabilities and the one with lower value will be subtracted from the one with higher value

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