a. what is the time that breaks this data set into an upper half and a lower hal
ID: 3175913 • Letter: A
Question
a. what is the time that breaks this data set into an upper half and a lower half? b. what is the time that separates the data set into the top 25% and the lower 75%? c. how many total oberservations were included in my sample? d. what is the general shape of the distribution? explain what statistics you used to determine the shape. Kitchen, Kayle x Problem 3 (15 Points) Many of you ride the Appalcart to campus (Boone's mode of public transportation). For those of you that do ride the bus, you must have also noticed that it is frequently not where it should be when it should be there. The representations below are representative of a random selection of the number of minutes that a given Appalcart bus is behind schedule. Appalcart Tardiness (In minutes) Appalcart Tardiness Descriptive Statistics Total Variable Count Mean StDev Minimum 01 Median Appalcart Tardiness 90 9.189 8.309 0.000 3.000 6.500 13.250 Variable Maximum IOR Appal cart Tardineas 36.000 10, 250 es aExplanation / Answer
a. what is the time that breaks this data set into an upper half and a lower half=median =6.5
b. what is the time that separates the data set into the top 25% and the lower 75%?: Q1 =3 and Q3=13.25
c. how many total oberservations were included in my sample? =count =90
d)d. what is the general shape of the distribution? explain what statistics you used to determine the shape.right skewed ; median
e)
e. does this data set display any outliers? if so, estimate the value of the outlier(s) : here IQR =Q3-Q1 =10.25
hence lower fence=Q1-1.5IQR =3-1.5*10.25=-12.375
as minimum is higher then this that is no bottom side outlier
for upper fence =Q3+1.5IQR =13.25+1.5*10.25=28.625
which is lower then maximum value therefore there are outliers at riught side ; and 36 is an outlier
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