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The following data are average yields in bushels per acre on four plots of land

ID: 3173671 • Letter: T

Question

The following data are average yields in bushels per acre on four plots of land for four different varieties of can. Yield (bushels per acre) is the response variable and corn variety is the treatment factor with four levels. Use these data for Questions on this task Calculate the treatment sample means. Consider the AOV test of hypothesis for treatments Ho:mu1 = mu2=mu3 = mu4 Ha: Not all the gi are equal, a = 0.05 Specify the critical region. Give the MS Factor and MS Error. Calculate the test statistic F, find the P-value, and make a decision about Ho

Explanation / Answer

Here we have to test the hypothesis that,

H0 : mu1 = mu2 = mu3 = mu4

H1 : Atleast one of the mean is differ than 0.

where mu1, mu2, mu3 and mu4 are four population means of yields.

Assume alpha = level of significance = 0.05

Here we have to test four means so we use one way ANOVA.

This we can done in EXCEL.

steps :

ENTER data into EXCEL sheet --> Data --> Data Analysis --> Anova : Single Factor --> ok --> Input Range : select all the data --> Grouped by : columns --> Alpha : 0.05 --> Output Range : select one empty cell --> ok

Then we get the output as :


F = 0.034658

P-value = 0.990989

MSfactor = 1.989142

MSerror = 57.39273

Here P-value > alpha

Fail to reject H0 at 5% level of significance.

Conclusion : There is sufficient evidence to say that the four population means are equal.

Anova: Single Factor SUMMARY Groups Count Sum Average Variance Column 1 4 305.4 76.35 179.2167 Column 2 4 301.03 75.2575 10.79889 Column 3 4 302.39 75.5975 11.90209 Column 4 4 307.24 76.81 27.65327 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 5.967425 3 1.989142 0.034658 0.990898 3.490295 Within Groups 688.7128 12 57.39273 Total 694.6802 15


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