The textbook expense for all courses of N = 112 E270 students is shown below. 51

Question

The textbook expense for all courses of N = 112 E270 students is shown below. 510 760 580 450 420 620 470 650 580 480 690 400 760 490 440 600 640 680 800 520 750 650 540 620 540 680 740 520 410 410 540 570 660 600 700 630 750 680 680 730 780 440 620 770 650 610 520 460 710 660 760 740 570 420 740 740 780 730 790 450 730 490 520 700 400 430 530 550 700 400 470 420 720 800 800 730 560 660 630 610 800 700 510 580 740 400 480 510 690 580 510 690 590 510 660 590 800 620 410 730 520 620 700 650 610 750 580 480 510 530 500 510 1 For random samples of size n = 20 selected from this population, the expected value of x is, a 667.31 b 635.53 c 605.27 d 544.74 Next THREE questions are related 2 A researcher reports survey results by stating that the standard error of the mean is $23.6. The population standard deviation is = $118. How large was the sample used in this survey? a 50 b 30 c 25 d 15 3 In the previous question, what is the probability that x is within ±$45 from the population mean? a 0.8792 b 0.8972 c 0.9155 d 0.9438 4 The 95% margin of error for the sampling distribution in the previous question is: a 47.94 b 46.26 c 44.74 d 43.22 The textbook expense for all courses of N = 112 E270 students is shown below. 510 760 580 450 420 620 470 650 580 480 690 400 760 490 440 600 640 680 800 520 750 650 540 620 540 680 740 520 410 410 540 570 660 600 700 630 750 680 680 730 780 440 620 770 650 610 520 460 710 660 760 740 570 420 740 740 780 730 790 450 730 490 520 700 400 430 530 550 700 400 470 420 720 800 800 730 560 660 630 610 800 700 510 580 740 400 480 510 690 580 510 690 590 510 660 590 800 620 410 730 520 620 700 650 610 750 580 480 510 530 500 510 1 For random samples of size n = 20 selected from this population, the expected value of x is, a 667.31 b 635.53 c 605.27 d 544.74 Next THREE questions are related 2 A researcher reports survey results by stating that the standard error of the mean is $23.6. The population standard deviation is = $118. How large was the sample used in this survey? a 50 b 30 c 25 d 15 3 In the previous question, what is the probability that x is within ±$45 from the population mean? a 0.8792 b 0.8972 c 0.9155 d 0.9438 4 The 95% margin of error for the sampling distribution in the previous question is: a 47.94 b 46.26 c 44.74 d 43.22

Explanation / Answer

1) average of above number is best estimate whcih is equal to 605.27 hence option C

2)as sample size=(/SE)2 =(118/23.6)2 =25 option C

3)P(-45/23.6<Z<45/23.6)=P(-1.9068<Z<1.9068)=0.9717-0.0283=0.9435 option D is correct

4)margin of error E =z*std error =1.96*23.6=46.26 option B

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