The January 1986 mission of the Space Shuttle Challenger was the 25th such shutt

Question

The January 1986 mission of the Space Shuttle Challenger was the 25th such shuttle mission It was unsuccessful due to an explosion caused by an O-ring seal failure. According to NASA, the probability of such a failure in a single mission was 1/59.909 Using this value of p and assuming all missions are independent, calculate the probability of no mission failures in 27 attempts Then calculate the probability of at least one mission failure in 27 attempts (Do not round your intermediate calculation and round your final answers to 4 decimal places.) According to a study conducted for the Air Force, the probability of such a failure in a single mission was 1/35 Recalculate the probability of no mission failures in 27 attempts and the probability of at least one mission failure in 27 attempts (Do not round your intermediate calculation and round your final answers to 4 decimal places.) Based on your answers to parts a and b. which value of p seems more likely to be true? Explain (Enter answer as a division like x/y.) How small must p be made in order to ensure that the probability of no mission failures in 27 attempts is 999? (Round your answers to 5 decimal places.)

Explanation / Answer

A)probabilty of no mission failure in 27 attemts P(0)=(1-1/59909)27 =0.9995

P(X>=1)=1-P(X=0) =1-0.9995=0.0005

b)P(X=0)=(1-1/35)27 =0.4572

P(X>=1)=0.5428

c)p=1/35

d)(1-p)27 =0.999

p=0.99996

q=1-0.99996=0.00004

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