Listed below are the amounts of mercury (in parts per million, or ppm) found in

Question

Listed below are the amounts of mercury (in parts per million, or ppm) found in tuna sushi sampled at different stores. The sample mean is 1.034 ppm and the sample standard deviation is 0.345 ppm. Use technology to construct a 90 % confidence interval estimate of the mean amount of mercury in the population.

Listed below are the amounts of mercury (in parts per million, or ppm) found in tuna sushi sampled at different stores. The sample mean is 1.034 ppm and the sample standard deviation is 0.345 ppm. Use technology to construct a 90% confidence interval estimate of the mean amount of mercury in the population. 1.42 1.49 0.61 0.85 0.69 0.99 1.19 What is the confidence interval estimate of the mean amount of mercury in the population? ppm

Explanation / Answer

For given sample, mean = 1.034 and std. dev. s = 0.345 and n = 7

For 90% CI, z critical value = 1.64

Hence lower limit = mean - z*s/sqrt(n) = 1.034 - 1.64 * 0.345/sqrt(7) = 0.8201

upper limit = mean - z*s/sqrt(n) = 1.034 + 1.64 * 0.345/sqrt(7) = 1.2479

Hence the confidence interval estimate of the mean amount of mercury in the population is

0.820 ppm < mu < 1.248 ppm

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