(14.09) Typing errors in a text are either nonword errors (as when the is typed
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Question
(14.09) Typing errors in a text are either nonword errors (as when the is typed as teh) or word errors that result in a real but incorrect word.
Spell-checking software will catch nonword errors but not word errors.
Human proofreaders catch 70% of word errors.
You ask a fellow student to proofread an essay in which you have deliberately made 10 word errors.
Step 1:
If X is the number of word errors missed, what is the distribution of X?
Step 2:
If Y is the number of word errors caught, what is the distribution of Y?
Step 3:
What is the mean number of errors caught?
Give your answer as a whole number.
Step 4:
What is the mean number of errors missed?
Give your answer as a whole number.
Step 5:
What is the standard deviation of the number of errors caught?
Give your answer to 4 decimal places.
Step 6:
What is the standard deviation of the number of errors missed?
Give your answer to 4 decimal places.
(14.09) Typing errors in a text are either nonword errors (as when the is typed as teh) or word errors that result in a real but incorrect word.
Spell-checking software will catch nonword errors but not word errors.
Human proofreaders catch 70% of word errors.
You ask a fellow student to proofread an essay in which you have deliberately made 10 word errors.
Step 1:
If X is the number of word errors missed, what is the distribution of X?
Step 2:
If Y is the number of word errors caught, what is the distribution of Y?
Step 3:
What is the mean number of errors caught?
Give your answer as a whole number.
Step 4:
What is the mean number of errors missed?
Give your answer as a whole number.
Step 5:
What is the standard deviation of the number of errors caught?
Give your answer to 4 decimal places.
Step 6:
What is the standard deviation of the number of errors missed?
Give your answer to 4 decimal places.
Explanation / Answer
Step 1:
If X is the number of word errors missed, then the distribution of x is
Step 2:
If Y is the number of word errors caught, then the distribution of Y is
Y is binomial with n = 10 and p = 0.7.
Step 3:
What is the mean number of errors caught?
mean= np =10*0.7=7
Step 4:
What is the mean number of errors missed?
mean= np =10*0.3=3
Step 5:
What is the standard deviation of the number of errors caught?
standard dev= sqrt(npq) =sqrt(10*0.7*.3) = 1.4491
Step 6:
What is the standard deviation of the number of errors missed?
standard dev= sqrt(npq) =sqrt(10*0.3*.0.7) = 1.4491
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