A researcher is studying the heights of men with a certain medical condition. Sh

Question

A researcher is studying the heights of men with a certain medical condition. She collects a sample of 38 such men and finds the mean height of the sample to be x^= 66.5 inches. Assume that the standard deviation of heights of men with the condition is the same as that of the general population, sigma = 2.8 inches. Find a 99% confidence interval for the true mean height of the population of mean with this condition. Provide the right endpoint of the interval as your Round your answer. An economic surveys 38 adults living is Townsburg about their salaries. The mean annual salaries for those surveyed was found to be $38982, with a standard deviation of $2292. Find a 90% confidence interval for the true mean annual salary of adults living in Townsburg. Provide the right endpoint of the interval as your answer.

Explanation / Answer

(1-alpha)*100% confidence interval for sample mean=mean± z(alpha/2)*sd/sqrt(n)

(7a) 99% confidence interval for sample mean=mean±z(0.01/2)*sd/sqrt(n)

=66.5±2.5758*2.8/sqrt(38)=66.5±1.17=(65.33,67.67)

(7b) right end point=67.67

(8a)

90% confidence interval for sample mean=mean±z(0.1/2)*sd/sqrt(n)

=39882±1.645*2292/sqrt(38)=39882±611.6=(39270.4,40493.6)

(8b) right end point=40493.6

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