Kane Manufacturing has a division that produces two models of hibachis, model A

Question

Kane Manufacturing has a division that produces two models of hibachis, model A and model B. To produce each model A hibachi requires 3 lb of cast iron and 6 min of labor. To produce each model B hibachi requires 4 Ib of cast iron and 3 min of labor. The profit for each model A hibachi is $5, and the profit for each model B hibachi is $4.50. If 1000 lb of cast iron and 20 labor-hours are available for the production of hibachis each week, how many hibachis of each model should the division produce each week to maximize Kane's profit? model A 760 hibachis models 1000 hibachis

Explanation / Answer

The simplex problem will be:

Maximize z = 5A + 4.5B

Subject to the constraints

3A + 4B < 1000

6A + 3B < 1200 (20 labor hours = 20*60 labor minutes = 1200 labor minutes)

A > 0

B > 0

Optimal solution for this is: z = 1320, A = 120, B = 160

So,

Model A: 120 hibachis

Model B: 160 hibachis

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