1.Based on the data shown below, calculate the correlation coefficient (to three

Question

1.Based on the data shown below, calculate the correlation coefficient (to three decimal places)

2.Based on the data shown below, calculate the regression line (each value to two decimal places)

y = x +

3.A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y).

The results of the regression were:

Use this to predict the number of situps a person who watches 7 hours of TV can do (to one decimal place)

x y 1 5.92 2 9.44 3 11.36 4 14.08 5 17 6 15.92 7 17.74 8 22.56 9 23.88 10 25.3 11 27.32 12 28.04 13 32.76 14 34.28

Explanation / Answer

1)from above

hence regression coefficient r=Sxy/(SSx*SSy )1/2=0.9922

2)

here b1=Sxy/Sxx=1.3817

and bo=Ybar-b1*Xbar=15.6

hence regression equation Y=15.6+1.3817X

3)here number of situps a person can do =-0.666*7+35.563 =30.901

x y (X-Xbar)^2 (Y-Ybar)^2 (X-Xbar)(Y-Ybar) Yi' (Y-Yi')^2 1.00 5.92 42.25 209.67 280.91 6.997143 1.16023673 2.00 9.44 30.25 120.12 201.66 9.059121 0.1450689 3.00 11.36 20.25 81.72 157.30 11.1211 0.05707374 4.00 14.08 12.25 39.94 103.65 13.18308 0.80447101 5.00 17.00 6.25 11.56 52.36 15.24505 3.07983215 6.00 15.92 2.25 20.07 64.51 17.30703 1.92386045 7.00 17.74 0.25 7.08 35.64 19.36901 2.6536768 8.00 22.56 0.25 4.67 -26.78 21.43099 1.27466581 9.00 23.88 2.25 12.11 -39.67 23.49297 0.14979452 10.00 25.30 6.25 24.01 -50.96 25.55495 0.06499698 11.00 27.32 12.25 47.89 -65.05 27.61692 0.08816331 12.00 28.04 20.25 58.37 -64.18 29.6789 2.68599681 13.00 32.76 30.25 152.77 -91.46 31.74088 1.03860737 14.00 34.28 42.25 192.65 -88.83 33.80286 0.22766531 Total 105.00 285.60 227.50 982.63 469.10 15.3541099 mean 7.50 20.40 SSX Ssy Sxy

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