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In statistics, we use the standard normal distribution to find out how extreme a

ID: 3172155 • Letter: I

Question

In statistics, we use the standard normal distribution to find out how extreme a score is. To do this, we compute the probability from the tail of the distribution to the score value. If the score value is less than the mean, we compute the probability from the left tail in to the score value, and if it is greater than the mean, we compute the probability from the right tail in to the score value. We can find these probabilities from published tables or directly in spreadsheets. The spreadsheet shows how to do this for both left tail and right tail probabilities for the first score value. You can apply the same formula to the other rows to find the missing values.

Notice that the formula requires inputting the mean and standard deviation. For the standard normal distribution this is 0 and 1, respectively. (columns B and C). Of course, you can change these values for normal distributions with different means and standard deviations

1) What is the p value (probability) associated with a score of 1.65 on the standard normal distrubution?

A) .5

B) .975

C) .025

D) .049

2) What is the p value (probability) associated with a score of -5 on the standard normal distrubution?

A) .5

B) .841

C) .049

D) .309

3) What is the p value (probabitlity) associated with a score of -1.65 on the standard normal distrubution?

A) .975

B) .5

C) .025

D) .049

1 x Mean stdev Heft tail aumulativo right tail aumulative 977 -1.960 0.000 1.000

Explanation / Answer

1 as it is right tailed test for 1.65 score p value =1-normsdist(1.65)=0.049

2)for 0.5 value ; p value =1-normsdist(0.5)=0.309

3) for left tailed test -1.65 =normsdist(-1.65)=0.049

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