An employee claims that drinking beer has no effect on the amount of time it tak

Question

An employee claims that drinking beer has no effect on the amount of time it takes for him to perform a particular task. The following data show how many seconds he took to perform the task after consuming various quantities of beer, measured in ounces: x = c(0, 12, 24, 36, 48, 60, 72); y = c(62, 51, 59, 74.5, 60.2, 83.7, 68.5); Consider the model Y_i = beta_0 + beta_1 x_i + epsilon_i, where epsilon_i's are iid N(0, sigma^2) sigma x = 252, sigma y= 458.9, sigma x^2 = 13104, sigma y^2 = 30798.23, sigma xy = 17553.6, sigma (x - x)^2 = 4032, sigma (y - y)^2 = 714.0571 sigma (x - x) (y - y) = 1033.2, y = beta_0 beta_1 x, sigma (y - y)^2 = 449.2997, Se = Squareroot (89.85994) = 9.479448, R^2 = 0.3708. Construct a 95% confidence interval for beta_1.

Explanation / Answer

b1 =Sxy/Sxx=0.25625

here std error of b1 =9.479448/(4032)1/2=0.149287

also for (n-2=5) degree of freedom and 95% Ci, t=2.570582

hence confidence interval =mean +/-t*std error =-0.12751 ; 0.09834

  

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.