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A City Colleges of Chicago x V Current Students xV Chamberlain college xVD course Home Prge x Take a Test Tiesha McG x C Statistics and probabilit x C Secure h ps://www. mathxl.com Test aspx?testld 151954382 /Student/Player Applied Managerial Statistics (100) Tiesha McGrew Quiz: Week 7 Quiz Time Remaining: 03:35:50 Submit Quiz This Question: 4 pts 4 of 15 (00 complete) This Quiz 60 pts possible A manufacturer claims that the life span of its tires is 48,000 miles. You work for a consumer protection agency and you are testing these tires. Assume the life spans of the tires are normally distributed. You select 100 tires at random and test them. The mean life span is 47,857 miles. Assume o 900. Complete parts (a) through (c). (a) Assuming the manufacturer's claim is correct, what is the probability that the mean of the sample is 47,857 miles or less? (Round to four decimal places as needed.) (b) Using your answer from part (a), what do you think of the manufacturers claim? The claim is Y because the sample mean be considered unusual since it Y within the range of a usual event, namely within of the mean of the sample means. (c) Assuming the manufacturer's claim is true, would it be unusual to have an individual tire with a life span of 47,857 miles? Why or why not? because 47,857 Y with the range of a usual event, namely within Y of the mean for an individual tire. Enter your answer in the answer box. S24 PM Ask me anything

Explanation / Answer

here std error =std deviation/(n)1/2=90

hence P(X<47857)=P(Z<(47857-48000)/90)=P(Z<-1.5889)=0.0560

the claim is not rejected...

please show options so that i can help you in that

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