Shortly after being put into service, some buses manufactured by a certain compa
ID: 3170683 • Letter: S
Question
Explanation / Answer
(a)
Since order of selection does not matter so number of ways of selecting 5 buses out of 25 is
C(25,5)= 53130
(b)
There are 8 buses with cracks and 17 without cracks so number of ways of selecting 4 buses from 8 buses with cracks and 1 out of 17 is
C(8,4)C(17,1) = 1190
(c)
Number of ways of selelcting 3 buses wth cracks is
C(8,3)C(17,2) = 7616
So requried probability is
7616 / 53130 = 0.1433
(d)
Number of ways of selelcting 4 buses or 5 buses with cracks is
C(8,4)C(17,1)+C(8,5)C(17,0) = 1246
So requried probability is
1246 / 53130 = 0.0235
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