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Function Low Med High # of interfaces 5 7 10 # of Queries 3 4 6 # of Files 7 10

ID: 3170632 • Letter: F

Question

Function Low Med High

# of interfaces 5 7 10

# of Queries 3 4 6

# of Files 7 10 15

You have been tasked by your new company with supporting the development of an internal campaign to invite employees to have healthier work habits such as taking at least two breaks from sitting in front of their computers during the work day; stretching at least once every 2 hours, etc. You have been named the manager for the manager for the project that has as objective to create an iterative and content rich website that not exceed $3,000. Please identify the major deliverables, milestones (with dates0 and sub-deliverables associated with your project) What organizational structure would be more appropriate for a small startup company developing apps for small business? Which structure would it morph into (if it does) after the start -up- has positioned itself? Consider the company American Furniture Warehouse (AFW). Do some research about AWF, focusing on its organizational culture. Choose two of the cultural dimensions and briefly describe each of them in light of your knowledge AFW. You work at a regional health care center and have been asked to calculate the expected cost for a software project in your organization. You know that historically your programmers can handle 8 function points each person -month and that the cost per programmer in your company is $5, 500 per month. The project whose costs you are estimating is based on the following requirements and the complexity weighing for these functions follow a standard internal formula, with the following parameters: The complexity weighting for these functions follows a standard internal formula, with the following parameters:

Explanation / Answer

In the problem, we test that function is independent of the complexity weights and also calculate the expected value.

Function Low Med High

# of Input 3 4 6

# of Output 4 5 7

# of interfaces 5 7 10

# of Queries 3 4 6

# of Files 7 10 15

Here we use the chi-square test and hypothesis is as follows

Ho: function is independent of the complexity weights

H1: function is not independent of the complexity weights

for the calculation purpose, we use R- software

> data<-matrix(c(3,4,6,4,5,7,5,7,10,3,4,6,7,10,15),5,3,byrow=TRUE)
> rownames(data)<-c("# of Inputs","# of Outputs","# of Interface","# of Queries","# of Files")
> colnames(data)<-c("Low","Med","High")
> chisq.test(data)

Pearson's Chi-squared test

data: data
X-squared = 0.0743, df = 8, p-value = 1

Warning message:
In chisq.test(data) : Chi-squared approximation may be incorrect
> chisq.test(data)$expected
Low Med High
# of Inputs 2.979167 4.0625 5.958333
# of Outputs 3.666667 5.0000 7.333333
# of Interface 5.041667 6.8750 10.083333
# of Queries 2.979167 4.0625 5.958333
# of Files 7.333333 10.0000 14.666667

here calculated p- value is 1 which is greater than 0.05 its means that null hypothesis is accepted at 0.05 level of significance. and expected value is also shown in the above.