e Edit View History Bookmarks Window Help Grace Con MA-105-ZNB, Pre-Calculus Alg

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e Edit View History Bookmarks Window Help Grace Con MA-105-ZNB, Pre-Calculus Algebra (3) Homework: HW 6 (1.6, 2.6, Interim Review) Score: 0.67 of 1 pt 60126 (25 complete) HW S 2.6.7 Diana has available 40 yards of fencing and wishes to enclose a rectangular area. K(a) Express the area A of the rectangle as a function of the width W of the rectangle. (b) For what value of W is the area largest? (c) What is the maximum area? Gra (a) Express the area as a function of the width. A(w)- Libr Enter your answer in the answer box and then click Check Answer. Clear All remaining ls Question 21 (1/1) Question 25 (1/1) Question 23 (1/1) Question 22 (1/1) Question 26 (1 /1) acBo

Explanation / Answer

fencing = perimeter

perimeter of rectangle= 2*(height+width)

A.)

40 = 2(H+W)

20-W=H

area of rectangle = H*W

area (as a function of W )= (20-W)*W

area=20W-W2

B.)

FOR max area d(area)/dW =0

d(20W-W2)/dW=0

20-2W=0

W=10

C.)

MAX area = H*W

= (20-10)*10 square yards

= 100 square yards

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