given a family with three children, find the probability of the event. The oldes
ID: 3167549 • Letter: G
Question
given a family with three children, find the probability of the event. The oldest is a boy and the youngest is a girl,given that there is at least one boy and at least one given a family with three children, find the probability of the event. The oldest is a boy and the youngest is a girl,given that there is at least one boy and at least one given a family with three children, find the probability of the event. The oldest is a boy and the youngest is a girl,given that there is at least one boy and at least oneExplanation / Answer
As there is at least 1 boy and 1 girl, the sample space is given as
S ={BBG, BGB, GBB, GGB, GBG, BGG}
Where B = Boys, G= Girls and the order represents the order of their births; i.e, for 'BBG' --> the eldest is a boy and the youngest is a girl
thus, n(S) = 6
The event A where The oldest is a boy and the youngest is a girl is given as,
A = {BBG, BGG}
i.e., n(A) = 2
thus the probability of event A occuring is
P(A) = n(A) / n(S) = 2 / 6 = 0.33
Answer: P(A) = 1/3 = 0.33
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