problems 17b and 19c 17. Let be an integer (a) Show that n is not divisible by 3
ID: 3167381 • Letter: P
Question
problems 17b and 19c
Explanation / Answer
17.b
if n is not divisible by 3 then
n = 3k + 1 or n = 3k +2
in both cases
n² - 3n + 2 is a multiple of 3
(3k + 1)² - 3(3k + 1) + 2 = 9k² - 3k = 3k(3k - 1)
(3k + 2)² - 3(3k + 2) + 2 = 9k² + 3k = 3k(3k + 1)
if n² - 3n + 2 is a multiple of 3,
then n² - 3n + 2 = 3k (*)
if n was divisible by 3, then
n = 3h
substitute in (*)
9h² - 9h + 2 = 3k
hence
3k - 9h² - 9h = 2
3(k - 3h² - 3h) = 2
k - 3h² - 3h = 2/3
which is impossible because h and k are integers
therefore n is NOT divisible by 3
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