According to a recent study, 1 out of 50,000 people will be diagnosed with cysti

Question

According to a recent study, 1 out of 50,000 people will be diagnosed with cystic fibrosis. Cystic fibrosis can be caused by a mutant form of the CFTR gene (dominant gene symbol is F and mutant is f). MAKE SURE TO USE CHI SQUARE METHOD. (E-O)^2/E

a. Using the rate of incidence above, what is the frequency of carriers of the cystic fibrosis allele for CFTR in the US? (3 pts0 b. In a clinical study, 400 people from the population mentioned in (a) were genotyped for BRCA1 gene. Listed below are the results. Are these results in Hardy- Weinberg equilibrium? Use Chi Square to show whether or not they are. (3 pts) ff of women BRCA1 genotype 390 BB 10 Bb bb

Explanation / Answer

a). The inheritance pattern of inheritance of cystic fibrosis is autosomal recessive. It is given that the frequency of occurrence in the US population is = 1 in 50, 000

Assuming that the gene coding for cystic fibrosis is f and its dominant wild type allele is F and is exhibits complete dominance,

The frequency of cc in the population is, ff or q2 = 1/50,000

The frequency of q = 0.0044

Assuming that the population is in H-W equilibrium, the frequency of dominant allele F or the frequency of p is = 1- 0.0044 = 0.9956

The frequency of CFTR carriers is = 2pq = 2*0.0044*0.9956 = 0.0087

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