Question Complete what is one advantage of using a swinging bucket rotors (also

Question

Question Complete what is one advantage of using a swinging bucket rotors (also known as horizontial rotors when separating biological particles? Swinging bucket rotors (also known as horizontal rotors) have the advantage that there is usually a clean meniscus of minimum area. Since the buckets are easy to interchange, this type of rotor is extremely versatile. swinging bucket rotors are smaller than fixed angle or other types of rotors, swinging bucket rotors have a larger sample volume capacity than fixed angle rotors. swinging bucket rotors are less expensive than fixed angle or other types of rotors. The equation we use in the lab to calculate dilutions is: C1 x VI-C2 x V2 Where C is concentration and V is volume. To make a solution with a concentration of C2 and a volume of V2 from a stock with a concentration C1 you just need to put these three numbers into the above equation and solve for V1, the volume of stock you will need to add. Remember to keep track of the units! If you wish to make 50 mls of a 1:10 dilution of a sample in a buffer then you would add: 5mls of the sample to 45 mis of the buffer 2.5 mls of the sample to 45 mls of the buffer o 10 mls of the sample to 50 mls of the buffer o 10 mls of the sample to 50 mis of the buffer A previous sample was already diluted 1:4. If you then added 1 enl of the diluted sample to aml of distilled water, your final sample dilution would be 1:20 ? 1:10 1340 1.5

Explanation / Answer

1. Centrifuge is a most important instrument in biology lab. The swinging bucket rotor has no fixed angle of rotation and hence when centrifuge begins the it swings such that the angle becomes 90 degree or almost horizontal. This offers minimal meniscus than the fixed angle ones. So option A is right.

2. In the formula Appy these values. C1 = 1 ; C2 1/10

V2 = 50; V1 is unknown. So

1 x V1 = 1/10 x 50

V1 = 5 ml. And the rest 45 will be diluent.

So option A is right.

3. C1 = 1/4. V1 = 1 ml ; V2 = 4+1=5

C2 is unknown

1/4 x 1 = C2 x 5

C2 = 1/20

Option A is right.

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