Using the Hardy-Weinberg equation for genotype frequency (p^2 + 2pq + q^2 = 1) f

Question

Using the Hardy-Weinberg equation for genotype frequency (p^2 + 2pq + q^2 = 1) fill out this chart with the expected genotype frequencies of this population, p = 03. q = 07. If you need a calculator you may use one. The goal of this is to test whether you understand this equation, rather than your ability to do calculations Record your results using the template below. An assistant has determined the expected frequency of each genotype for your population's offspring based on observations of homozygous recessive frequency in the offspring population. The frequencies for the offspring population are as follows: Is evolution occurring? How do you know?

Explanation / Answer

Answer:

Part 1: This part is missing some important information. Total number of population is required to measure the expected frequency. However, in gross we can assume A is dominant and signifies p population and recessive a is represented by q. If we assume 1000 was the total population, then the gross expected frequency will be like:

EXPECTED GENOTYPE FREQUENCIES

AA= (0.3X0.3), Aa= (0.3X0.7), aa= (0.7X0.7)

if 1000 is the total no of individual then

AA= (0.3X0.3)X1000= 90

Aa= (0.3X0.7)X1000= 210

aa= (0.7X0.7)X1000= 490

Part 2: As the result presented in the problem indicates maximum number of recessive percentage, it is presumable that some genetic alteration is hapenning in the population. The scenario is close to 'bottle neck effect' and hence, evolution is going on here.

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