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PCB 3063L 10. In humans, the rh factor is inherited as a dominant gene (R). Indi

ID: 3164590 • Letter: P

Question

PCB 3063L 10. In humans, the rh factor is inherited as a dominant gene (R). Individuals with this allele are referred to as rh positive. Two (2) heterozygous individuals (Rr) decided to reproduce a. What is the probability of four (4) rh positive children? [1) b. What is the probability of four (4) rh negative boys? [!) c. What is the probability of two (2) rh positive boys and two (2) rh negative girls? [1] d. If they have five (5) children, what is the probability that the first two (2) will be rh negative and the last three (3) will be rh positive? [1l e. What is the probability of three (3) rh positive children out of eight (8) children? [1) You will need to use the binomial expansion formula for this problem: xt(n-x)

Explanation / Answer

10 . With a cross with Rh X Rh.

Out of four children 3 will be Rh positive and 1 will be negative.

So probability of being Rh positive is 3/4.

A.So probability of four Rh positive children is 3/4 X 3/4 X 3/4 X 3/4 = 81/256

B. Probability of four Rh negative children is 1/4 X 1/4 X 1/4 x1/4 = 1/256

C. probability of 2 Rh positive and 2 Rh negative children is 3/4 x3/4x1/4x 1/4= 9/256

D. Probability of out of 5 first 2 will be Rh negative and last 3 will be Rh positive is 1/4 X 1/4 X 3/4 X 3/4 x3/4 = 256/1024

e. Probability of 3 out of 8 children will be positive is

{8!/(5! X 3!)} X (3/4)3 X (1/4)5 = 0.023071289.