Two masses (M_1 and M_2) are a system. Let E = K + U be the total mechanical ene

Question

Two masses (M_1 and M_2) are a system. Let E = K + U be the total mechanical energy of the system and p be the total momentum of this system. A mass m_1 slides on a frictionless horizontal plane and collides and sticks to a mass m_2 that is at the bottom of a frictionless ramp. What is conserved in the collision? Both E and p are conserved in the collision. E is conserved in the collision Neither E nor p is conserved in the collision. p is conserved in the collision. After the collision, masses m_1 and m_2 slide together up the curved ramp and come to a rest. What is conserved during this motion? Both E and p are conserved during the motion. Neither E nor p is conserved during the motion. E is conserved during this motion. p is conserved during this motion. Now suppose there is friction between the masses and the curved ramp. Again, the masses m_1 and m_2 slide together up the ramp and come to a rest. What is conserved during the motion? Neither E nor p is conserved during this motion. p is conserved during this motion. Both E and p are conserved during this motion. E is conserved during this motion.

Explanation / Answer

part 1)

as the block m1 sticks to block 2

the collision is inelastic

mechanical energy is not conserved

hence , the correct option is 4)

as momentum is conserved

part 2)

Now , when the block moves up the incline

as the force is acting , p is not conserved

but the total energy is conserved as there is no friction

the correct option is 3)

part 3)

if there is friction then

option 1)

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