physics Two spaceships approach Earth with equal speeds (es viewed from Earthi b
ID: 3163388 • Letter: P
Question
physics
Explanation / Answer
1) The length of the meter stick in the frame of the observer L = 1 m / gamma
gamma = 1 m / 0.4 = 2.5
gamma = 1 / sqrt [1 - beta2]
sqrt [1 - beta2] = 1 / 2.5
1 - beta= 0.16
beta = 0.92 c
if v is the speed of spacecraft 1 in the frame of reference of the Earth then Ux = v
Ux' = -0.92 c
Ux' = ux - v / [1 - v ux'/c2]
-0.92 c = -v - v / [1 - v[-v]/c2]
0.92 = 2 beta / 1 - beta2
0.92 beta2 - 2 beta + 0.92 = 0
beta = 0.66 c
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