Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

In the figure , C1 = C5 = 8.0 F and C2= C3 = C4 = 4.8 F . The applied potential

ID: 3163375 • Letter: I

Question

In the figure , C1 = C5 = 8.0 F and C2= C3 = C4 = 4.8 F . The applied potential is Vab = 230 V .

Part A What is the equivalent capacitance of the network between points a and b? Express your answer using two significant figures.

Part B Calculate the charge on capacitor C1. Express your answer using two significant figures.

Part C Calculate the potential difference across capacitor C1. Express your answer using two significant figures.

Part D Calculate the charge on capacitor C2. Express your answer using two significant figures.

Part E Calculate the potential difference across capacitor C2. Express your answer using two significant figures.

Part F Calculate the charge on capacitor C3. Express your answer using two significant figures.

Part G Calculate the potential difference across capacitor C3. Express your answer using two significant figures

Part H Calculate the charge on capacitor C4. Express your answer using two significant figures.

Part I Calculate the potential difference across capacitor C4. Express your answer using two significant figures.

Part J Calculate the charge on capacitor C5. Express your answer using two significant figures.

Part K Calculate the potential difference across capacitor C5. Express your answer using two significant figures.

C C. C. C be 3 2 a

Explanation / Answer

Here ,

for the equivalent capacitor

first C3 and C4 are in series

1/C6 = 1/4.8 + 1/4.8

C6 = 2.4 uF

Now, for C2 and C6 in parallel

C7 = 2.4 + 4.8 = 7.2 uF

for C1 , C5 and C7 in parallel

1/Ceq = 7.2 + 1/8 + 1/8

Ceq = 2.57 uF

the equivalent capacitance of the network between points a and b is 2.57 uF

part B)

charge on capacitor C1 = V * Ceq

charge on capacitor C1 = 230 * 2.57 uC

charge on capacitor C1 = 591.4 uC

part C)

potential across C1 = 591.4/8 V

potential across C1 = 73.9 V

part D)

charge on capacitor 2 = 591.4 * 4.8/(2.4 + 4.8)

charge on capacitor 2 = 394.3 uC

the charge on capacitor 2 is 394.3 uC

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote