how do you figure out this problem? ENGR 391/ HW 3 Q5) Consider a fluid flow bet
ID: 3162867 • Letter: H
Question
how do you figure out this problem?
Explanation / Answer
given velocity profile u(y) = 110(0.05*y - y^2)
a) assume a incremental height of water of thickness dy, at height y
assume channel depth of d
area of this water element = d*dy
incremental flow rate, dF = rho*v(y)*d*dy
dF = rho*110*(0.05y - y^2)*d*dy
integrating from y = 0 to y = H
F = rho*110*d*(0.05H^2/2 - H^3/3)
H = 0.05 m
d = 1 m
F = 2.2916 kg m/s
b) Average channel velocity = v
then v*d*H*rho = F = 2.2916
v = 2.2916/0.05*1*1000 = 0.0458 m/s
c) u(y) max is at y = H/2
u(H/2) = 110(0.05*H/2 - H^2/4)
now H = 0.05 cm
u(H/2) = 0.06875m/s
d) V/Umax = 0.66618
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.