1. (a) Determine the digital resolution of a 12 ppm proton spectrum collected on

Question

1. (a) Determine the digital resolution of a 12 ppm proton spectrum collected on a 300 MHz NMR instrument. Number of data points collected for this spectrum was 1K (1024 bytes). [Hint: On a 300MHz instrument, 1PPM=300Hz]
(b). What would be the resolution of the above spectrum if 2000 data points were collected?
C. If we increase the spectral width from 12 to 20 ppm and keep all other acquisition parameters same as in problem 1(a) and collect a proton spectrum, what would be the acquisition time and resolution of the newly acquired proton spectrum?

Explanation / Answer

a) For a 300MHz NMR, 3600 Hz is required to scan 12 ppm of a proton structure.

digital resolution = 2(spectral width) / no. of points

= 2 (3600) / 1024

= 7200/1024

= 7.01325 Hz/point

b) if the no. of points is 2000, then the required resolution is 7200/2000 = 3.6 hz/point

c) For a 20 ppm proton spectrum, 6000 Hz is required. Keeping all other acquistitions paramaters same as in 1.a then the required digital resolution is 6000 / 1024 = 5.859 Hz/ point

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