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One problem on a page. Front side only. Draw and label a figure Show equation. q

ID: 3161903 • Letter: O

Question

One problem on a page. Front side only. Draw and label a figure Show equation. quantities. units. and your work. Place box around the answer. An astronaut launched from earth to Proximal Centauri travels a distance of 4.24 ly moving at a speed of 0.978c. (Away from the earth is the positive direction.) How long does the trip take (in years) according to the observers on earth? How long does the trip take (in years) according to the astronaut? THE Fighter heading away from the Death Star can release a probe that travels 0.550c relative to the Fighter. (Away from the Death Star is the positive direction) Find the probe's velocity as measured by the Death Star if it is released towards the Death Star. Find the probe's velocity as measured by the Death Star if it is released away from the Death Star. Find the velocity of a laser beam as measured by the Death Star if the beam travels from the fighter towards the Death Star. Planet X and Planet Z are on a collision course, moving towards each other at a relative speed of 0.400c. A spaceship sent from Planet X Approaches Planet Z at 0.800c as observed by those on Planet Z. Find the velocity of the spacecraft relative to Planet X. (Away from Planet X a the positive direction) A stationary observer. Jack, sees two spaceships. A and B. moving towards him from opposite directions at speeds of v_a = 0.800c and v_a = 0.900c respectively. (Let A be on the left and B on the right with to-the-right be the positive direction.) According to an observer on A. at what velocity is he approaching Jack? According to an observer on A. at what velocity is he approaching spaceship B? According to an observer on B. at what velocity is he approaching Jack? According to an observer on B. at what velocity is he approaching spaceship A?

Explanation / Answer

1) a) Length of the trip according to observers on earth

t = d / v = 4.24 c / 0.978

= 4.34 years

b) Length of the trip according to astronaut

delta t' = delta t * sqrt [1 - (v/c)2]

= [4.24 ly/ 0.978 c] * sqrt [1 - (0.978 c/c)2]

= 4.24 ly * 0.209

= 0.904 years