Two ligation reactions between a vector and an insert are prepared. In one case

Question

Two ligation reactions between a vector and an insert are prepared. In one case ("A") the ligation was done with a dephosphorylated vector and in a second case ("B") the vector had not been dephosphorylated. Transformation in bacteria of equal amounts of DNA from the two ligation reactions yielded the following results:

Transformation of ligation mixture "A": 50 colonies

Transformation of ligation "B": 5000 colonies

Given the results obtained, what is the minimum number of colonies that must be screened in the transformation of ligation mixture "B" to find one recombinant clone?

Explanation / Answer

Transformation of ligation mixture A = 50 colonies

Transformation of ligation B = 5000 colonies

minium number of colonies = 50,000

recombinat clone   = 1000

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