The missing entry p is about 0.20 0.00 0.16 0.44 0.32 The probability that the c
ID: 3160404 • Letter: T
Question
The missing entry p is about 0.20 0.00 0.16 0.44 0.32 The probability that the container will contain at least two defective fasteners is about 0.20 0.29 0.14 0.71 0.09 The average number of defective fasteners per container of 5,000 is about 2.5 1.2 0.11 0.98 1.5 Problems 14 and 15 pertain to the following situation a woman buys 20 one-dollar lottery tickets per The probability of any ticket being a winning ticket is 0.10 or 10%. The probability that in any one month at least three of the tickets that the woman buys are tickets is about 0 2000 0.8670 0.3231 0.3000 0.6769 The average number of winning tickets that the woman buys each month is about 0 2 1.3 2.1 1.5 2.0 A researcher wishes to estimate the mean level of student loan debt of bachelor's degree graduation, with 95% confidence and to within $500. Assuming that the standard deviation loan debt to be about $3,000, the estimated minimum sample size needed is about 98 139 10 67 195Explanation / Answer
14. Probability of success, p=0.10, number of trials, n=20 and specific number of success is r=3. Use binomial distribution to Bernoulli trials. P(X,r)=nCr(p)^r(q)^n-r
P(X>=3)=1-P(X<3)=1-[P(X=0)+P(X=1)+P(X=2)]=1-0.6769=0.3231 (c)
b) Mean, E(X)=np=20*0.10=2 (e)
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.