Problem #20: To compare two brands of cigarettes, Brand 1 and Brand 2, for their
ID: 3160245 • Letter: P
Question
Problem #20: To compare two brands of cigarettes, Brand 1 and Brand 2, for their tar content, a sample of 60 was inspected from Brand 1 and a sample of 40 from Brand 2. The results of the tests are summarized as follows. Let mu_1 be the mean tar content of all cigarettes of Brand 1 and mu_2 be the mean tar content of all cigarettes of Brand 2, and perform a hypothesis test at the 0.05 significance level to determine whether or not Brand 1 has a lower tar content than Brand 2. Make sure to state the null and alternative hypotheses, state whether it is a left-, right-, or two-tailed test, show all necessary steps to arrive at your conclusion, and state your final conclusion in the context of this problem.Explanation / Answer
Here we have to test the hypothesis that,
H0 : Brand1 has a equal tar content than brand2.
H1 : Brand1 has a lower tar content than brand2.
The test is one sided with < (left tailed test) sign.
Assume alpha = level of significance = 5% = 0.05
Given values are :
For brand1 :
n1 = 60
X1bar = 15.4
s1 = 1.732
For brand2 :
n2 = 40
X2bar = 16.8
s2 = 2.000
First we have to check whether variances are equal or not.
For that the hypothesis is,
H0 : Variances are equal.
H1 : Variances are not equal.
The test statistic is,
F = larger variance / smaller variance
This we can done by using TI-83 calculator.
steps :
STAT --> TESTS --> D:2-SampFTest --> ENTER --> Highlight on Stats --> ENTER --> Input all the values --> select alternative not= --> Calculate --> ENTER
Test statistic F = 1.333
P-value = 0.3131
P-value > alpha
Accept H0 at 5% level of significance.
COnclusion : The variances are equal.
So we use pooled variances.
Now we test here two means using two sample t-test with equal variances.
Ti-83 steps :
STAT --> TESTS --> 4:2-SampTTest --> ENTER --> Highlight on Stats --> ENTER --> Input all the values --> select alternative " < mu2 " --> ENTER --> Pooled : Yes --> ENTER --> Calculate --> ENTER
The test statistic is,
t = -3.7207
df = 98
P-value = 1.6567E-4 = 0.00016567
P-value < alpha
Reject H0 at 5% level of significance.
Conclusion : There is sufficient evidence to say that brand1 has a lower tar content than brand2.
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