The accompanying data resulted from an experiment in which weld diameter x and s

Question

The accompanying data resulted from an experiment in which weld diameter x and shear strength y (in pounds) were determined for five different spot welds on steel. A scatterplot shows a pronounced linear pattern. The least-squares line is y = -948.38 + 8.60x. Because 1 lb = 0.4536 kg, strength observations can be re-expressed in kilograms through multiplication by this conversion factor: new y = 0.4536(old y). What is the equation of the least-squares line when y is expressed in kilograms? (Give the answer to two decimal places.)

Explanation / Answer

y(old) = -948.38 + 8.60x

Then

y(new) = 0.4536 y(old)

= 0.4536*(-948.38 + 8.60x)

= -430.185168 + 3.90096x

y(new) = -430.19 + 3.90x

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