A survey of automobile ownership was conducted for 200 + DGC = families in a par

Question

A survey of automobile ownership was conducted for 200 + DGC = families in a particular city. The results of the study showing ownership of automobiles of United States and foreign manufacturers are given below:(a) Complete the above Table. (b) What is the probability that a randomly selected family will own both U.S. and Foreign trucks? (c) What is the probability that a randomly selected family will not own both U.S. and Foreign trucks? (d) What is the probability that a randomly selected family will not own a U.S. truck, but will own a Foreign truck? (c) What is the probability that a randomly selected family will own a U.S. truck, but not a Foreign truck? (f)Given that a randomly selected family owns a U.S. truck, what is the probability that they will also own a foreign truck? (g) Given that a randomly selected family owns a U.S. truck, what is the probability that they will not own a foreign truck? (h) Given that a randomly selected family owns a Foreign truck, what is the probability th t they will also own a U.S. truck? (i) Given that a randomly selected family owns a Foreign truck, what is the probability that they will not own a U.S. truck? (j) Are the events "Own a U.S. truck" and "Own a foreign truck" independent? Justify your claim.

Explanation / Answer

b.

Out of 403 family, 120 owns boths U.S. truck and foreign truck. So required probability is

P(U.S. truck and foreign truck) = 120 /403 =0.2978

c.

Out of 403 family, 143 not owns boths U.S. truck and foreign truck. So required probability is

P(not U.S. truck and not foreign truck) = 143 /403 =0.3548

d.

Out of 403 family, 30 not owns U.S. truck but own foreign truck. So required probability is

P(not U.S. truck and own foreign truck) = 30 /403 =0.0744

e.

Out of 403 family, 110 owns U.S. truck but not own foreign truck. So required probability is

P(own U.S. truck and not own foreign truck) = 110 /403 =0.2730

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