Question
for portion (c), I know the answer is "c" but how do I calculate the end portion, "between____ and ___ hours?"
9.2.30 Ex. Score: 3 of 5 pts HW Score: 96.92% (6 of 65 pts) 14 of 14 complete A nutrionist wants to determine how much time nationally people spend eating and drinking Suppose for a random sample of 1026 people age 15 or older, the mean amount of time spent A nutritionist wants to eating or drinking per day is 1.77 hours with a standard deviation of 0.64 hour. Complete parts (a) through (d) below U ine aismoumon or tne sampic mean wu arways De approxmatery normau (b) In 2010, there were over 200 milion people nationally age 15 or older. Explain why this, along with the fact that the data were obtained using a random sample, satisfies the requirements for constructing a confidence interval The sample size is greater than 5% of the population. The sample size is less than 5% of the population. The sample size is greater than 10% of the population. The sample size is less than 10% of the population A (c) Determine and interpret a 90% confidence m terval for the mean amount oftme Amenca s age 15 or c der spend ea ng and each day mkn Select the correct choice below and fill in the answer boxes, if applicable, in your choice Type integers or decimals rounded to three decimal places as needed Use ascending order.) OA The nutriti stis 90% conEdent that the amount oft nesper teat ng ordmang per day for any mania sber een andhours. OB There is a 90% probability that the mean amount oftm e spent eating ordmang per day is between and hours @c The nutrition stis 9% confident that the mean amount oftme spent eating orarmkn g perdayts between andhours. OD The requirements for constructing a confidence interval are not satisfied Click t to select and enter your answer(s), then click Check Answer Clear All
Explanation / Answer
c)
Note that
Margin of Error E = z(alpha/2) * s / sqrt(n)
Lower Bound = X - z(alpha/2) * s / sqrt(n)
Upper Bound = X + z(alpha/2) * s / sqrt(n)
where
alpha/2 = (1 - confidence level)/2 = 0.05
X = sample mean = 1.77
z(alpha/2) = critical z for the confidence interval = 1.644853627
s = sample standard deviation = 0.64
n = sample size = 1026
Thus,
Margin of Error E = 0.032864993
Lower bound = 1.737135007
Upper bound = 1.802864993
Thus, the confidence interval is
( 1.737135007 , 1.802864993 ) [ANSWER, OPTION C BLANKS]
