Some experts believe that 17% of all freshwater fish in a country have such high

Question

Some experts believe that 17% of all freshwater fish in a country have such high levels of mercury that they are dangerous to eat. Suppose a fish market has 200 fish tested, and 27 of them have dangerous levels of mercury. Test the hypothesis that this sample is not from a population with 17% dangerous fish, assuming that this is a random sample. Use a significance level of 0.05. Comment on your conclusion. State the null and alternative hypotheses. H_0: p = 0.17 H_1: p notequalto 0.17 H_0: p notequalto 0.17 H_a: p = 0.17 H_0: p > 0.17 H_a: p 0.17 Determine the z-test statistic. (Round to two decimal places as needed.) Find the p-value. Choose the correct conclusion. Do not reject H_0. The population proportion is significantly different from 0.17.

Explanation / Answer

Test statistic. The test statistic is a z-score (z) defined by the following equation.

z = (p - P) /

Where = sqrt[ P * ( 1 - P ) / n ]

first we calculate the value of ,

= sqrt [(0.17 * 0.83) / 200] = sqrt(0.00071) = 0.026
z = (p - P) / = (.135 - .17)/0.026 = -1.346 =-1.35 rounded to two decimal

The test statistic Z = -1.35

put the function in excel =normsdist(-1.35) and enter you will get p-value 0.089

Since the P-value (0.089) is greater than the significance level (0.05), we cannot reject the null hypothesis.

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.