[The following information applies to the questions displayed below.] A sample o

Question

[The following information applies to the questions displayed below.] A sample of 40 observations is selected from a normal population. The sample mean is 64, and the population standard deviation is 8. Use the 0.01 significance level. H0: = 65 H1: 65 23. Required information Is this a one- or two-tailed test? Two-tailed test One-tailed test 24. Required information What is the decision rule? Reject H0 if z < -2.58 or z > 2.58 Reject H0 if -2.58 < z < 2.58 25. Required information What is the value of the test statistic? (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.) Value of the test statistic 26. Required information What is your decision regarding H0? Fail to reject H0 Reject H0 27. Required information What is the p-value? (Round z value to 2 decimal places and final answer to 4 decimal places.) p-value

Explanation / Answer

Set Up Hypothesis
Null Hypothesis H0: U=65
Alternate Hypothesis H1: U!=65
Test Statistic
Population Mean(U)=65
Given That X(Mean)=64
Standard Deviation(S.D)=8
Number (n)=40
we use Test Statistic (Z) = x-U/(s.d/Sqrt(n))
Zo=64-65/(8/Sqrt(40)
Zo =-0.7906
| Zo | =0.7906
Critical Value
The Value of |Z | at LOS 0.01% is 2.58
We got |Zo| =0.7906 & | Z | =2.58
Make Decision
Hence Value of |Zo | < | Z | and Here we Do not Reject Ho
P-Value : Two Tailed ( double the one tail ) - Ha : ( P != -0.7906 ) = 0.4292
Hence Value of P0.01 < 0.4292, Here We Do not Reject Ho

[ANSWER]
1. TWO Tailed, Reject H0 if z < -2.58 or z > 2.58
2. Zo =-0.7906
3. Failed Reject Ho
4. ( P != -0.7906 ) = 0.4292

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