need serious help with #5,6. and 7 (c) 84% of flightx l\'avingan airport \"rive

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need serious help with #5,6. and 7

(c) 84% of flightx l'avingan airport "rive a z Given each P-valuc and level of sigaificnce, deterine hypothesis should be rejected. p-0.009. -001 For problems 3-9, sest the claim using an a s 1est. State the valuets) or the P-value (you do not need so give both) and whrther the claim is rejected, not rejecteol, suppocted, or not supported 5. It is claimed that the mean soore on a ted is at least 75, A ample of 141s scores has mean 70,2. If the ted scores are noemally distributed with standard deviation o 1t, sest the claim using O1e e 0.10 Given n 9, and p-0.34e , test the claim that p-0.3 ising = 0.01 A clam is made hat less than 65% of the cmployees at a large empeny are sti,bed with their job. Amotg random sample of 180 employees, 56.4% say hat they are satisfied with their jos Test the elain using -0.0s 7.

Explanation / Answer

Font size is low, and hazy.

5) Perform 1 -sample t test (small sample size, n<30, sample standard deviation is knwon).

t=(xbar-mu)/(s/sqrt n), where xbar is sample mean, s is sample standard devaiyion and n is sample size.

=(76.2-75)/(1/sqrt 14)

=4.49

p value at df=13, and alpha=0.10 is 0.000304. The p value is less than alpha=0.10. Reject null hypothesis to cocnlude that mean score on a test is at least 75.

7) Perform 1-proportion Z test.

Z=(Ps-Pu)/sqrt[Pu(1-Pu)/N], where Ps, Pu are sample and population proportion, N is sample size.

=(0.564-0.65)/sqrt [0.65(1-0.65)/180]

=-2.42

p value is 0.00776. The p value is less than alpha=0.05. Reject null hypothesis to cocnclude that less than 65% of employess in ;arge organization are satisfie dwith their job.

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